Question

plz solve it as soon as possible

Answer 1

Here is the answer

Answer 2

j${( \sqrt[3]{ {x}^{4}y } \times \frac{1}{ \sqrt[3]{x {y}^{7} } } )}^{ - 4}) \\ \\ \sqrt[3]{ {x}^{4} y} \: \: \: can \: be \: written \: as \\ x \sqrt[3]{xy} \\ similiarly \\ \sqrt[3]{x {y}^{7} } \: can \: be \: written \: as \\ {y}^{2} \sqrt[3]{xy} \: \\ \: so \: the \: equation \: becomes \\ {(x \sqrt[3]{xy} \times \frac{1}{ {y}^{2} \sqrt[3]{xy} }) }^{ - 4} \\ \\ \sqrt[3]{xy} \: \: will \: get \: cancelled \\ {(x \times \frac{1}{ {y}^{2} } )}^{ - 4} \\ which \: becomes \\ { \frac{( {y}^{2} }{x} )}^{ 4 } \\ \\ the \: answer \: - \\ \frac{ {y}^{8} }{{x}^{4} }$