Math, asked by Utkarsh6295, 3 months ago

plz Solve it Bez urgent​

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Answered by kavya3171
31

(cosec tita - cot tita)^2 = 1-cos tita/1+cos tita

we have,

(cosec tita - cot tita)^2

=(1/sin tita-cos tita/sin tita)^2

=(1-cos tita/sin tita)^2

=(1-cos tita)^2/sin^2 tita = (1-cos tita)^2/1-cos^2 tita

[ sin^2 tita = 1-cos^2 tita]

=(1-cos tita)^2/(1-cos tita)(1+cos tita)

=1-cos tita/1+cos tita

bro I hope it's help you☺☺I thought that I will spam this question but you said urgent so I was answered you

which class bro?

Answered by Anonymous
3

We have,

(cosecθ−cotθ) ²

= 1 cos θ

(_____− ___. )²

sinθ sin θ

= 1−cosθ

( ________. )²

sinθ

hope it will help you

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