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First term, a = 5
Last term, l = 45
Common difference = d
Sum of AP of n terms =(n/2)(a+l)
Sum = 400
On substituting value of a and l,
We get, n = 16
Number of terms = 16
l = a + (n-1)d
On substituting value of a, l and n,
We get,d =8/3
Hope you like it....
Mark as brainliest....
Last term, l = 45
Common difference = d
Sum of AP of n terms =(n/2)(a+l)
Sum = 400
On substituting value of a and l,
We get, n = 16
Number of terms = 16
l = a + (n-1)d
On substituting value of a, l and n,
We get,d =8/3
Hope you like it....
Mark as brainliest....
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