Question

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Answer 1

Step-by-step explanation:

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Answer 2

QUESTION-:

${x}^{2} + 7x + 7$

GIVEN THAT :-

"a" and "b". are the zeroes of this equation

TO FIND :-

The value of -

$\frac{1}{a} + \frac{1}{b} - 2ab$

EXPLANATION:-

If "a" and "b" are the zeros of this equation

then the value of

$a + b = - 7$

and

$ab \: = 7$

SOLUTION:-

The value of

$\frac{1}{a} + \frac{1}{b} - 2ab \: = \frac{a + b - 2( {ab)}^{2} }{ab} \\ \\ = \frac{ - 7 - 2 {(7)}^{2} }{7} \\ = \frac{ - 7 - 98}{7} \\ = \frac{ - 115}{7}$

ANSWER:-

$\frac{ - 115}{7}$