Question

plz solve it fast friends

Answer 1

Let the numerator be x

Denominator is 25 more than numerator

So, let denominator be x + 25

Original fraction = $\dfrac{x}{x + 25}$

7 added to the numerator and denominator,

Numerator = x + 7

Denominator = x + 25 + 7 = x + 32

After adding 7 to numerator and denominator, the new fraction becomes $\dfrac{1}{2}$


According to the question,

$\dfrac{x + 7}{x + 32} = \dfrac{1}{2}$

➾ 2(x + 7) = 1(x + 32)

➾ 2x + 14 = x + 32

➾ 2x - x = 32 - 14

➾ x = 18

∴ Numerator ➾ x


➾ $\green{\boxed{\green{\boxed{\red{\textsf{18}}}}}}$


∴ Denominator ➾ x + 25

➾ 18 + 25

➾ $\green{\boxed{\green{\boxed{\red{\textsf{43}}}}}}$



∴ Original fraction = $\boxed{\boxed{\boxed{\dfrac{18}{43}}}}$

Answer 2

Answer: Your answer will be: (c) 18/43

OK let's see how:

Step-by-step explanation:

Let the numerator be x

Then,

Denominator will be x+25(It is given that the denominator is 25 more than   the numerator)

Now, 7 is added both to numerator and denominator

so,

New Numerator = x+7

⇒new denominator =  x+25+7

⇒new denominator= x+32

Now,

new NUMERATOR/ new DENOMINATOR= 1/2    (GIVEN IN THE QUESTION)

A/Q

⇒ x+7/x+32=1/2

(by cross multiplication)

⇒ 2(x+7)=x+32

⇒ 2x + 14 = x+32

⇒x= 18

Thus,

Fraction = Numerator/Denominator

fraction = 18/18+25

fraction = 18/43

Cheers.

Happy Learning