Question

plz solve it... first don't just write the answer...


need quality answers.​

Answer 1

${\sf{\underline{\underline{\pink{Solution:-}}}}}$

Sum of zeroes ${( \alpha + \beta)}$ = - 1

product of zeroes ${( \alpha ×\beta)}$ = - 6

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As we know

$\sf{p(x) = x^2 - ( \alpha + \beta)x + ( \alpha × \beta )}$

$\sf{=> x^2 - ( - 1)x + ( -6)}$

$\sf{=> x^2 + x - 6}$

Therefore, Option (2) is correct