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To factorize x^3 + 1/x^3 - 2, take LCM of the expression.
Expression becomes, (x^6 - 2 x^3 + 1) / x^3. Now numerator is easily factorisable as (x^3 - 1)^2
So final expression is (x^3 - 1)^2 / x^3.
for further factorization with real coefficients, we can use
x^3 - 1 = (x - 1)*(x^2 + x + 1)
So (x^3 - 1)^2 / x^3 = [(x - 1)^2 * (x^2 + x + 1)^2] / x^3
Hope it helps!
Expression becomes, (x^6 - 2 x^3 + 1) / x^3. Now numerator is easily factorisable as (x^3 - 1)^2
So final expression is (x^3 - 1)^2 / x^3.
for further factorization with real coefficients, we can use
x^3 - 1 = (x - 1)*(x^2 + x + 1)
So (x^3 - 1)^2 / x^3 = [(x - 1)^2 * (x^2 + x + 1)^2] / x^3
Hope it helps!
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