Question

plz solve it guys

answer of
(a) is 30
(b) is 50​

Answer 1

For Triangle a) :

Given :

• Base is 18 cm and Perpendicular Height is 24 cm .

To Find :

• Value of x .

Solution :

Using Pythagoras Theorem :

$\longmapsto\tt{{(x)}^{2}={(B)}^{2}+{(P)}^{2}}$

$\longmapsto\tt{{(x)}^{2}={(18)}^{2}+{(24)}^{2}}$

$\longmapsto\tt{{(x)}^{2}=324+576}$

$\longmapsto\tt{x=\sqrt{900}}$

$\longmapsto\tt\bf{x=30\:cm}$

So , The Value of x is 30 cm ..

_______________________

For Triangle b) :

Given :

• Base is 30 cm and Perpendicular Height is 40 cm .

To Find :

• Value of x .

Solution :

Using Pythagoras Theorem :

$\longmapsto\tt{{(x)}^{2}={(B)}^{2}+{(P)}^{2}}$

$\longmapsto\tt{{(x)}^{2}={(30)}^{2}+{(40)}^{2}}$

$\longmapsto\tt{{(x)}^{2}=900+1600}$

$\longmapsto\tt{x=\sqrt{2500}}$

$\longmapsto\tt\bf{x=50\:cm}$

So , The Value of x is 50 cm ..

Answer 2

Step-by-step explanation:

Here

both triangles are right angled

in triangle (a)

$Given \begin{cases}Perpendicular{}_{(p) }=24cm \\ Base {}_{(b)}=18cm \end {cases}$

To find:-

value of x =hypontenuse

Solution:-

According to Pythagorean theory

${:}\longrightarrow$${\boxed{{h}^{2}={p}^{2}+{b}^{2}}}$

${:}\longrightarrow$${x }^{2}={24}^{2}+{18}^{2}$

${:}\longrightarrow$$x={\sqrt {576+324}}$

${:}\longrightarrow$$x={\sqrt {900}}$

${:}\longrightarrow$${\underline{\boxed{\bf {x=30cm}}}}$

$\therefore$hypontenuse =30cm

In triangle(b)

$Given\begin{cases}perpendicular{}_{(p)}=40cm \\ base {}_{(b)}=30cm \end {cases}$

To find:-

Value of x=hypontenuse

Solution:-

Again according to Pythagorean theory

${:}\longrightarrow$${x}^{2}={40}^{2}+{30}^{2}$

${:}\longrightarrow$${x}^{2}=1600+900$

${:}\longrightarrow$$x={\sqrt{2500}}$

${:}\longrightarrow$${\underline{\boxed{\bf{x=50cm}}}}$

$\therefore$hypontenuse =50cm.