Question

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Answer 1

Answer:

GIVEN :

If n (A) = 20, n (B) = 28 and n( A\cup B) = 36n(A∪B)=36 then n (A\cap B)n(A∩B)

TO FIND :

The value of n (A\cap B)n(A∩B)

SOLUTION :

Given that n (A) = 20, n (B) = 28 and n( A\cup B) = 36n(A∪B)=36

The formula in Set theory is given by :

n( A\cup B) = n(A)+n(B)-n (A\cap B)n(A∪B)=n(A)+n(B)−n(A∩B)

Now substituting the values in the above formula we get,

36 = 20+28-n (A\cap B)36=20+28−n(A∩B)

36=48-n (A\cap B)36=48−n(A∩B)

n (A\cap B)=48-36n(A∩B)=48−36

= 12

∴ n (A\cap B)=12n(A∩B)=12

∴ the value of n (A\cap B)n(A∩B) is 12

Step-by-step explanation:

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Answer 2

Answer:

fai. If n(A)=20,n(B)=28 and n(AUB)=36 then n(A intersection B) = fai.