Question

plz solve it in ur own handwriting

Answer 1

since
3x=sec@,

then
x=sec@/3,

also
3/x=tan@,

then 1/x=tan@/3,

now
(x²-1/x²) = [(sec@/3)² - (tan@/3)²],

=[sec²@/9 - tan²@/9],

=1/9[sec²@-tan²@],

then
(x²-1/x²)=1/9,

since
sec²@-tan²@=1