Question

plz solve it..... it's urgent

Answer 1

Multiplying both nr. and dr. by 1-sinA we get

(1-sinA)²/1-sin²A

1+sin²A-2sinA/cos²A ( since 1-sin²A = cos²A)

Now separating the terms we get 

1/cos²A+sin²A/cos²A-2sinA/cos²

sec²A+tan²A-2 tanA secA which is nothing but (secA-tanA)²

Answer 2

Here is ur answer
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