Question

plz solve it
it would be a graet help​

Answer 1

Answer:

It is a solution of your question

Answer 2

Please mark as brainliest

Answer:

Given: O is the centre of circle c(O,r).

To Prove: ∠AOC=∠AFC+∠AEC

Step-by-step explanation:

Proof: In ∆BEC, using exterior angle theorem.

Exterior angle theorem property: Sum of two interior angle of triangle is equal to opposite exterior angle.

So, we get:

∠ABC=∠AEC+∠BCD

On multiplying both the sides with 2:

2∠ABC=2∠AEC+∠BCD

as, Angle subtended on circle is half angle subtended at centre.

2∠ABC=∠AOC

∠AOC=∠AEC+∠BCD+∠AEC+∠BCD

∠AOC=∠AEC+∠BCD+∠ABC

But, ∠ABC=∠ADC (Angles subtended on same arc are equal)

∠AOC=∠AEC+∠BCD+∠ADC

In ΔFDC using exterior angle theorem,

∠AFC=∠BCD+∠ADC

Thus, ∠AOC=∠AFC+∠AEC

Hence, proved.