Math, asked by shraddha20048, 1 year ago

plz solve it its urgent qn 10 a​

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Answered by amankumaraman11
2

{ \blue{Let  \:  \: the \:  \:  CP \:  \:  be \:  \:  x }}\\ { \blue{then,  \: the \:  \:  MP \:  \:  will \:  \:  be  \:  \:  \frac{115x}{100} =  \frac{23x}{20}  }} \\ { \blue{Now,  \: SP \:  \:  is \:  \:   (\frac{23x}{20} \times  \frac{95}{100})}} \\ { \blue{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = \frac{2185x}{2000}  }}

Here, While comparing SP & CP, SP is found larger.

So,

{ \green{Profit = SP - CP}} \\ { \green{ \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 2185x - 2000x}}\\ { \green{ \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   = 185x}} \\  \\  \\ { \green{Profit\% =  (\frac{profit}{CP} \times 100) }} \\ { \green{ \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   =  \frac{185}{2000} \times 100 }} \\ { \green{ \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{185}{20}  = 9.25\% }}


shraddha20048: whatever
amankumaraman11: Hey !!! Manish !!! My answer is not copied from somewhere, I have solved it by myself....
Answered by manish5365
1

sorry for answering late.

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shraddha20048: tq
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