Question

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Answer 1

Since

molecular mass=2× Vapour density

Molecular mass=2×59=118

given in the question

Carbon is 40.68%by mass

assuming that one mole of compound is taken

the weight of compound =molecular mass

therefore Carbon's percentage mass will be

=Mass of carbon÷total mass ×100

but this is equal to 40.68%

thus

40.68%=mass of carbon/118×100

mass of carbon=40.68×118÷1009=48

Mass of Hydrogen/total mass ×100=5.08%

Mass of hydrogen/118×100=5.08%

Mass of hydrogen =5.08×118÷100=6

%of oxygen=100%-(5.08+40.68)%

=54.24%

Mass of oxygen/total mass×100=54.24%

Mass of oxygen=54.24×118÷100=64

Mass of Carbon=48

Mass of Oxygen=64

Mass if Hydrogen=6

We know that molecular wt of

1. Carbon=12
2. Oxygen=16
3. Hydrogen=1

therefore their moles in compound

1. Carbon=48/12=4
2. Oxygen=64/16=4
3. Hydrogen=6/1=6

THEREFORE THE MOLECULAR FORMULA IS

C4H6O4