Math, asked by Riya090914, 7 months ago

Plz solve it on paper...!!!
⚠️ Don't give unusual answers...!!!​

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Answers

Answered by Anonymous
2

Answer:

Here is your answer buddy

Step-by-step explanation:

(i) (0, 2)

x – 2y = 4

0 – 2(2) = 4

0 – 4 = 4

-4 ≠ 4

∴ (0, 2) is not a solution

(ii) (2, 0)

x – 2y = 4

2 – 2(0) = 4

2 – 0 = 4

2 ≠ 4

∴ (2, 0) is not a solution

(iii) (4, 0)

x – 2y = 4

4 – 2(0) = 4

4 – 0 = 4

4 = 4

∴ (4, 0) is a solution

(v) (1, 1)

x – 2y = 4

1 – 2(1) = 4

1 – 2 = 4

-1 ≠ 4

∴ (1, 1) is not a solution

Answered by Anonymous
1

\underline{\pink{\bf{\purple{\dag}\:Answer:-}}}

Given equation:

\sf\red{⟶}x − 2y = 4

In question given (1,1)

Putting values in equation:

\sf\red{⟶}1−2×1 = 4

\sf\red{⟶}1−2 is not equal to 4

(1,1) is not a solution

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