Plz solve it!!! Question: Find the smallest number which when divided by 35,56 and 105 leaves a reminder of 6 in each case.
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LCM=2^3*7*5*3=840. Now add to 5 840, we get 845. Therefore smallest number which, when divided by 35,56 and 105, leaves a remainder of 5 in each case is 845.
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