Question

plz solve it quickly​

Answer 1

Answer:

Given:

$\bf \star \: m_1 = m_2 = m \\ \\ \bf \star \: u_1 = u \\ \\ \bf \star \: u_2 = 0$

Solution:

$\bf \underline{Let \: \: v_1 \: \: and \: \: v_2 \: \: be \: \: their \: \: velocities \: \: after \: \: collision}$

According to momentum conversation,

$\bf \: \large \: mu = m(v_1 + v_2)$

(or)

$\bf \large \: u = v_1 + v_2........(1)$

By definition,

$\bf \large \: e = \frac{v_2 -v_1 }{u - 0}$

(or)

$\bf \large \: v_2 - v_1 = eu..........(2)$

Solve the EQ (1) and (2)

we know that,

$\bf \large \: v_1 = \frac{(1 - e)u}{2}$

And,

$\bf \large \: v_2 = \frac{(1 + e)u}{2}$

Therefore,

$\bf \large \boxed{ \frac{v_1}{v_2} = \frac{1 - e}{1 + e} }$