Plz solve ..It's from the chapter - Congruent Triangles
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In triangle ADB and BCD
DB = DB (Common)
AD = BC (Given)
Angle ADB = angle DBC
triangle ADB ≈ triangle BCD (SAS)
AB = DC (by cpct)
DB = DB (Common)
AD = BC (Given)
Angle ADB = angle DBC
triangle ADB ≈ triangle BCD (SAS)
AB = DC (by cpct)
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