Question

plz solve it
solve the question in the attachment
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Answer 1

Answer:

Given coordinates of sides of triangle are:

A(1,-1)

B(-4,6)

C(-3,-5)

$x1 = 1 \\ x2 = - 4 \\ x3 = - 3 \\ y1 = - 1 \\ y2 = 6 \\ y3 = - 5$

Area of triangle =

$= \frac{1}{2} (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)) \\ \\ = \frac{1}{2} (1(6 + 5) - 4( - 5 + 1) - 3( - 1 - 6)) \\ \\ = \frac{1}{2} (1(11) - 4( - 4) - 3( - 7)) \\ \\ = \frac{1}{2} (11 + 16 - 21) \\ \\ = \frac{1}{2} (27 - 21) \\ \\ = \frac{1}{2} \times 6 \\ \\ = 3 \: {units}^{2}$

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Answer 2

Area = 3 sq.units

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