plz solve it step by step
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Step-by-step explanation:
please draw a qud ABCD and produce BA to meet and DE||CA
at E Join E to C
Proof-- ar∆EAC=ar∆ADC
(two triangle on the same base AC and lies between same ||line.
Add ∆ABC on both sides
ar ∆(EAC+ABC)=ar∆ADC+ar(ABC)
Now_
ar∆ {EBC}= ar qud{ABCD
please try it once more yourself
Hope it help u.
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