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dear your answer is
area of I = √11(11-1)(11-5)(11-5) = 6√110 {by using area of triangle formula}
area of II = 1*6.5 = 6.5
area of III = by pythagoras find height of trapezium i.e. h = √1²-0.5² = 0.5√3
area of IV and V = 2*[1/2*1.5*6] = 8
adding all we get 78.3 cm² {app.}
hope it will help you
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area of I = √11(11-1)(11-5)(11-5) = 6√110 {by using area of triangle formula}
area of II = 1*6.5 = 6.5
area of III = by pythagoras find height of trapezium i.e. h = √1²-0.5² = 0.5√3
area of IV and V = 2*[1/2*1.5*6] = 8
adding all we get 78.3 cm² {app.}
hope it will help you
please mark it as brainliest
thank you
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