Question

plz solve it
$1 - 2ab - ( {a}^{2} + {b}^{2} )$
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Answer 1

$1 - 2ab - ( {a}^{2} + {b}^{2} ) \\ = 1 - 2ab - {a}^{2} - {b}^{2} \\ =1 - {a}^{2} - {b}^{2} - 2ab \\ = 1 - ( {a}^{2} + {b}^{2} + 2ab) \\ = 1 - {(a+b) }^{2} \\ = ( {1)}^{2} - ( {a + b)}^{2} \\ = (1 + a + b)(1 - a - b)$

Hence, your answer is (1+a+b)(1-a-b)✌

Answer 2

Aditya kya bekar dp lagaya hai

please change it