Question

plz solve it to me of class x

Answer 1

b)

From the diagram,

resistor 6 ohm & 3 ohm are in parallel. so the resultive resistance is

=> [6×3]÷[6+3]

=> [18]÷[9]

=> 2 ohm

And also both the 2 ohms are in series .so the the resultive resistance is

=> 2+2

=> 4 ohms

:-)Hope it helps u.

Answer 2

HELLO FRIEND!

10. (a) From the definition of potential difference, we get that it is the work done in bringing an unit positive charge from one point of the conductor to another.
Thus, Work done = Charge brought x Potential difference applied
or W = QV
(W = Work, Q = Charge, V = Potential difference).

From the above relation, we can find the work done.
Given that, Q = 300C
and V = 100V

So, W = QV = 300C x 100V
= 30000 Joule
or 3 x 10⁴ J


(b) NOTE: The 6Ω and 3Ω resistors are combined in parallel.
So, first, let's find the effective resistance of the parallel combination.

[tex] \implies \frac{1}{R} = \frac{1}{6} + \frac{1}{3} \\ \implies \frac{1}{R} = \frac{3}{6} \\ \implies \frac{1}{R} = \frac{1}{2} \\ \implies R = 2 [/tex]

Thus, effective resistance of the parallel combination is 2Ω

Now, another 2Ω resistor is connected in series.
Thus, effective resistance between points A and B = 2Ω + 2Ω = 4Ω



HOPE MY ANSWER IS SATISFACTORY....
THANKS!