Question

plz solve it. tomorrow is my test

Answer 1

let the two digit number be 10A+B,

then

according to the question,

A+B=11 ..................eq(1),


number obtained after reversing the digits=10B+A,

now

(10A+B) - (10B+A) = 9,

10A+B-10B-A=9,

9A-9B=9,

9(A-B)=9,

then

A-B=1 .............eq(2),

now solve eq(1) and eq(2), We get

A=6,

B=5,

therefore

original number=10A+B,

=10×6+5,

=60+5=65

Answer 2

Answer:65

Step-by-step explanation: