Question

plz solve it .....urgent......and solve in copy and pin it....plz​

Answer 1

Answer:

2%

Step-by-step explanation:

Assume that the cost price of the 1st phone is ₹100

Considering the deal of phone 1,

As it is given, there is 4% loss, the selling price will be = ₹96

=>CP = 100

=>SP = 96

So, for CP = 1, SP = 96/100

Now,

=>CP = ₹8000

=>SP = 96/100 × 8000

=>SP = 7680

Thus, the selling price of 1st phone = Rs. 7680

_____________________

Assume that the cost price of the 2nd phone is ₹100

Considering the deal of phone 2,

There is an 8% profit

=>The selling price will be = ₹108

=>CP = 100

=>SP = 108

So, for CP = 1, SP = 108/100

given CP = ₹8000

Hence,

=> SP = 108/100 × 8000

=>SP= ₹8640

Thus, the selling price of 2nd phone = Rs. 8640

____________________

Here, the total selling price will be = ₹(7680 + 8640) = ₹16320

Now, We know that

Total selling price > total cost price i.e. Rs. 16320 > Rs. 16000

There is a profit of ₹(16320 – 16000) = ₹ 320

___________________________

Now, the overall profit percentage will be-

Profit% = (Profit/Total Cost Price) × 100 = (320/16000) × 100 = 2

Therefore, there is a total of 2% profit for the whole transaction.

❤️Hope this helps you ❤️