plz solve it urgently, question no. 12, 13, 14
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12. total salary = 30600
increment =20 percent
= 20/100.(30600)
= 7200 is the increment
increment =20 percent
= 20/100.(30600)
= 7200 is the increment
Answered by
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question no.12:
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let his salary before the increment be 'x'
increment = 20% = 20% of x = ₹0.2x
new salary = ₹30600
x + 0.2x = 30,600
1.2x = 30,600 => x = ₹25,500
Answer: his salary was ₹25,500.
question no. 13 :
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attended school = 204 days
his attendance = 85%
85% = 204
1% = 204 ÷ 85 = 2.4
100% = 2.4 × 100 = 240 days
Answer:school was opened for 240 days.
question no.14:
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let B's income = ₹100
A's income = 20% less than B's income
A's income = 100 - 20% of 100
= 100 - 20 = ₹80
thus A's income = ₹80
difference = 100 - 80 = ₹20
difference% = (difference × 100)/A's income
= (20× 100)/ 80
= 25%
Answer:
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B's income is 25% more than A's income.
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let his salary before the increment be 'x'
increment = 20% = 20% of x = ₹0.2x
new salary = ₹30600
x + 0.2x = 30,600
1.2x = 30,600 => x = ₹25,500
Answer: his salary was ₹25,500.
question no. 13 :
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attended school = 204 days
his attendance = 85%
85% = 204
1% = 204 ÷ 85 = 2.4
100% = 2.4 × 100 = 240 days
Answer:school was opened for 240 days.
question no.14:
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let B's income = ₹100
A's income = 20% less than B's income
A's income = 100 - 20% of 100
= 100 - 20 = ₹80
thus A's income = ₹80
difference = 100 - 80 = ₹20
difference% = (difference × 100)/A's income
= (20× 100)/ 80
= 25%
Answer:
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B's income is 25% more than A's income.
TheLostMonk:
thanks for the brainliest :)
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