Math, asked by DaRvl, 3 months ago

plz solve it...
which one u can❤️❤️​

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Answered by llbrainlyllstarll
28

Answer:

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I) x²+8x−48=0

⇒x²+8x+16−64=0

⇒(x+4)²−(8)²=0

⇒(x+12)(x−4)=0

∴x=−12,x=4

ii)  x²+11x+24=0

x²+8x+3x+24=0 (by splitting the middle term)

⇒x(x+8)+3(x+8)=0

⇒(x+8)(x+3)=0

⇒x=−8 or x=−3

I HOPE IT'S HELP YOU MADAM

Answered by sreyasinharkl
2

hello \:mate

i) x²+8x−48=0

⇒x²+8x+16−64=0

⇒(x+4)²−(8)²=0

⇒(x+12)(x−4)=0

∴x=−12,x=4

ii)  x²+11x+24=0

x²+8x+3x+24=0 (by splitting the middle term)

⇒x(x+8)+3(x+8)=0

⇒(x+8)(x+3)=0

⇒x=−8 or x=−3

I hope my answer helps you...

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