plz solve it who is best in math fast as us can
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the answer is in the picture
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shiveejaiswal25:
mark as brainlist
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Given thickness of wood = 3 cm
Length of open box = 1.48 m = 148 cm
Breadth of open box = 1.16 m = 116 cm
Height of open box = 8.3 dm = 83 cm
Inner length, l = outer length – twice width
= 148 – 6 = 142 cm
Inner breath = 116 – 6 = 110 cm
Inner height = 83 – 3 = 80 cm [since it is an open box]
Area of inner surface = T.S.A - lb
2(lb + bh + hl) – lb
= 2[142 x 110 + 110 x 80 + 80 x 142] – [142 x 110]
= 55940 cm²
Cost of painting inner surface = Rs (50/100) x (55940/100) = Rs 279.90
Length of open box = 1.48 m = 148 cm
Breadth of open box = 1.16 m = 116 cm
Height of open box = 8.3 dm = 83 cm
Inner length, l = outer length – twice width
= 148 – 6 = 142 cm
Inner breath = 116 – 6 = 110 cm
Inner height = 83 – 3 = 80 cm [since it is an open box]
Area of inner surface = T.S.A - lb
2(lb + bh + hl) – lb
= 2[142 x 110 + 110 x 80 + 80 x 142] – [142 x 110]
= 55940 cm²
Cost of painting inner surface = Rs (50/100) x (55940/100) = Rs 279.90
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