Math, asked by Anonymous, 1 year ago

PLZ SOLVE IT...........xd​

Attachments:

Answers

Answered by ANGRY74
4

Here is your answer☺️

1. (3x+7)^2 - 84x = (3x-7)^2

= LHS

= (3x+7)^2

= (3x)^2 + 2(3x+7) + (7)^2

= 9x^2 + 42x + 49

= 9x^2 + 42x + 49 - 84

= 9x^2 - 42x + 49

= RHS

= (3x-7)^2

= (3x)^2 - 2(3x+7) + (7)^2

= 9x^2 - 42x + 49

Hence, LHS = RHS

2. (9p-5q)^2 + 180pq = (9p+5q)^2

= LHS

= (9p-5q^2

= (9p)^2 - 2(9p×5q) + (5q)^2

= 81p^2 - 90pq + 25q^2

= 81p^2 - 90pq + 25q^2 + 180pq

= 81p^2 + 90pq + 25q^2

= RHS

= (9p+5q)^2

= (9p)^2 + 2(9p×5q) + (5q)^2

= 81p^2 + 90pq + 25q^2

Hence,LHS = RHS

3. (4/3m-3/4n) + 2mn = 16/9m^2 + 9/16n^2

= (4/3m-3/4n)^2

= (4/3m)^2 - 2(4/3m×3/4n) + (3/4n)^2

= 16/9m^2 - 2mn + 9/16n^2

= 16/9m^2 + 9/16n^2 - 2mn + 2mn

= 16/9m^2 + 9/16n^2

Hence, LHS = RHS

4. (4pq+3pq)^2 - (4pq-3pq)^2 = 48pq^2

= (4pq+3q)^2

= (4pq)^2 + 2(4pq×3pq) + (3q)^2

= 16pq^2 + 24pq^2 + 9q^2

= (4pq-3q)^2

= (4pq)^2 - 2(4pq×3q) + (3q)^2

= 16pq^2 - 24pq^2 + 9q^2

= 16pq^2 + 24pq^2 + 9q^2 - 16pq^2 + 24pq^2 - 9q^2

= 48pq^2

Hence, LHS = RHS

5. (a+b)(a+b)+(b-c)(b+c)+(c-a)(c+a) = 0

= (a)^2-(b)^2+(b)^2-(c)^2+(c)^2-(a)^2

= 0

Hence, LHS = RHS

Answered by manmohantiwari61
2

Answer:

1st ans is right ans.................

Similar questions