Question

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Answer 1

Step-by-step explanation:

Method 1

ok here is ur answr..

area of trapezium BAPC = 1/2 (sum of parallel sides ) h

1/2 ( 15+30) 15/2

1/2 * 25 * 15/2

$\frac{1}{2} \times 45 \times \frac{15}{2}$

$\frac{675}{4}$

168.75 m²

now area of whole park is = 168.75 * 2 = 337.5 m²

Method 2

area of square in 2nd figure = 15*15 = 225m²

area of triangle = 1/2 * base * height

1/2 *15 * 15 ( as whole height is 30 and side of square is 15 so height of triangle will be 15 m )

1/2* 225

$\frac{225}{2}$

112.5 m²

so area of park = 225 + 112.5 = 337.5 m²

So by these 2 methods the area will be 337.5 m²

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Answer 2

Using first method:-

=> Area of quadrilateral ACBP = (15/2)(15) = 225/2

area of triangle ACF = 1/2 (15) (15/2) = 225/4

total area of PFCB = 675/4

=> Area of quadrilateral AEDP = (15/2)(15) = 225/2

area of triangle AEF = 1/2 (15/2)(15) = 225/4

total area of EDPF = 675/4

=> Total area of park = 675/2

Answer:

Using second method:-

area of quadrilateral (square) = 15 × 15 = 225

and area of triangle = 1/2 (15)(15) = 225/2

total area = 675/2

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