Question

plz solve karo jaldi plz


...


urgently​

Answer 1

10^(-11) can be written as = 1/(10)^11

and we know that

a^m × a^n × a^ b = a ^(m+n+b)

so,

our numberator will be = 6.67 × 7.4 × 10^48 ×6

so, our denominator will be = (3.84)² × (10)^(11+8+8) = (3.84)² × (10)^27

Now we know that ,

a^m/a^n = a^(m-n)

so,

we get,

6*6.67*7.4*10^(48-27)/(3.84)²

6*6.67*7.4*10^21/(3.84)²

This can be solved by dividing by 2 further

3*6.67*3.7*10^21/(1.92)²

= 20.08*10^(21) (Approx)

(Hope it helps you)

Answer 2

Answer:

According to me Answer is 2×10^22