plz solve my first question of physics
of 50 points
Answers
CORRECT ANSWER IS OPTION D
➡️Draw FBD of two blocks
➡️ assuming that blocks moves with common acceleration
ac = 10/4+6 = 10/10= 1m/s²
➡️draw FBD of block b (on which external force is not applied )
➡️ Required frictional force
f = Mb × ac = 6× 1 = 6N
since, limiting friction (maximum available static friction)= 0.2×4×10 =8N
NOTE:- If ac (common acceleration) is ≤ a max then,
aA=aB=aCommon
Required frictional force is less then limiting friction hence, both blocks willove together with common acceleration.
Answer:
Answer:
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CORRECT ANSWER IS OPTION D
➡️Draw FBD of two blocks
➡️ assuming that blocks moves with common accelerationac = 10/4+6 = 10/10= 1m/s²
➡️draw FBD of block b (on which external force is not applied )
➡️ Required frictional forcef = Mb × ac = 6× 1 = 6Nsince, limiting friction (maximum available static friction)= 0.2×4×10 =8N
then,aA=aB=aCommonRequired frictional force is less then limiting friction hence, both blocks willove together with common acceleration.