plz solve my math question because tomorrow is my math exam
plz help me
I will mark u as a brainlist
1- If x and y vary inversely and x = 25 , when y=3 . find y , when x =15
2- If x and y vary inversely and y =45. find x when constant of variation =9
Answers
Answered by
1
HEYA MATE,
HERE IS UR ANSWER.
Thanks for asking this question.
The answer is 5.
X=1/y*k
K is a constant.
So, xy=k
So,25*3=k=75
Now, x is 15 &k is 75.
So, 15*y=75
Hence y is 75/15=5
Y=5.
INVERSE PROPORTION :
----------------------------------
Two quantities x and y are said to vary in inverse proportion if
xy = k -----------( 1 )
where k is a constant.
according to our problem
y = 45 ,
k = 9 .
put these values in ( 1 ),
xy = k
x × 45 = 9
x = 9 / 45
x = 1/5
if y = 45 then x = 1/5
I HOPE IT HELPS U.
HERE IS UR ANSWER.
Thanks for asking this question.
The answer is 5.
X=1/y*k
K is a constant.
So, xy=k
So,25*3=k=75
Now, x is 15 &k is 75.
So, 15*y=75
Hence y is 75/15=5
Y=5.
INVERSE PROPORTION :
----------------------------------
Two quantities x and y are said to vary in inverse proportion if
xy = k -----------( 1 )
where k is a constant.
according to our problem
y = 45 ,
k = 9 .
put these values in ( 1 ),
xy = k
x × 45 = 9
x = 9 / 45
x = 1/5
if y = 45 then x = 1/5
I HOPE IT HELPS U.
0BRAINLY01:
wlcm
Answered by
1
hope it is helpful you
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