Question

plz solve my question ​

Answer 1

Hope this helps you...

Answer 2

SOLUTION ☺️

$= > ( \frac{x}{x + 1} ) {}^{2} - 5( \frac{x}{x + 1} ) + 6 = 0 \\ \\ = > put \: \frac{x}{x + 1} = y \: then \: above \: the \: equation \: becomes \\ = > {y}^{2} - 5y + 6 = 0 \\ = > {y}^{2} - 3y - 2y + 6 = 0 \\ = > y(y - 3) - 2(y - 3) = 0 \\ = > (y - 3) \: (y - 2) = 0 \\ = > y - 3 = 0 \: \: \: or \: y - 2 = 0 \\ = > y = 3 \: \: \: \: \: \: or \: \: y = 2 \\ \\ = > when \: y =3 \\ = > \frac{x}{x + 1} = 3 \\ = > 3x + 3 = x \\ = > 3x - x = - 3 \\ = > 2x = - 3 \\ = > x = - \frac{3}{2} \\ \\ = > when \: y \: = 2 \\ = > \frac{x}{x + 1} = 2 \\ = > 2x + 2 = x \\ = > 2x - x = - 2 \\ = > x = - 2$

hope it helps ✔️