plz solve my question
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Step-by-step explanation:
TRIANGLE PQR,
ANGLE Q = ANGLE R
ANGLE RPS = ANGLE Q+ANGLE R (EXTERIOR ANGLE PROPERTY) ------ (1)
ANGLE RPS = ANGLE SPT + ANGLE TPR
ANGLE SPT = 1/2 ANGLE RPS (SINCE PT BISECTS ANGLE RPS)
ANGLE SPT = 1/2 (ANGLE Q + ANGLE R) (FROM (1))
ANGLE SPT = ANGLE Q (SINCE ANGLE Q = ANGLE R)
THESE ANGLES FORM A PAIR OF CORRESPONDING ANGLES ONLY WHEN PT IS PARALLEL TO QR.
HENCE PROVED.
PLS MARK ME AS BRAINLIEST
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