Question

plz solve my question​

Answer 1

Answer:

3 x + 2 y=13

Step-by-step explanation:

Firstly, finding the point of intersection of the first two lines.

Two lines are:x + 2 y +5=0----equation 1

                      3 x + 4 y +1=0----equation 2  

From, 1st line equation , 2 y = -(x +5)----equation 3

putting equation 3 in equation 2

   3 x + 2(2 y)+1=0

=>3 x + 2(-x -5)+1=0

=>3 x -2 x =10-1=9

=>x=9

putting it in equation 1 we get 2 y=-5-9=-14

                                                 =>y=-7

Thus, the point of intersection of the two lines is (9,-7)

now, we have two points through which required line passes, thus the line equation required will be y - a=m(x-b){where m=slope of the line =d-b/c-a;

                                      (a,b) is the first point and (c,d) is the  second point}

{here (a,b)=(9,-7) and (c,d)=(3,2)}

=>y-(-7)={(2-(-7))/3-9}(x-9)

=>y+7=(9/(-6))(x-9)

=>3(x-9)=-2(y+7)

=>3 x -27+2 y +14=0

=>3 x +2 y=13

Thus, the required line equation is 3 x + 2 y=13