Plz solve my question :-An electric lamp of resistance 100ohm, a toaster of resistance 50 ohm and a water filter of resistance 500 ohm are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances and what is the current through it?
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Answered by
2
well, we use parallel circuit system here.
So the total resistance R will be given by:-
r comes out to be 500/16
Calculating current, by V=IR,
I is 176/25.
Since same source is used, V will remain 220V
since current is equal,
R=V/I again.
R comes out to be 22000/706 or 31.16 ohm
So the total resistance R will be given by:-
r comes out to be 500/16
Calculating current, by V=IR,
I is 176/25.
Since same source is used, V will remain 220V
since current is equal,
R=V/I again.
R comes out to be 22000/706 or 31.16 ohm
Answered by
1
total current of circuit=current through electric iron
v=IR( where I=total current of the circuit and R=total resistance)
220=R×(2.2+0.5+5)
220=R×3.2
R=220/3.2
R=68.7 ohm
v=IR( where I=total current of the circuit and R=total resistance)
220=R×(2.2+0.5+5)
220=R×3.2
R=220/3.2
R=68.7 ohm
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