plz solve my question tommorow is my exam........One fourth of a no. exceeds one-fifth of its succeding no. is 3, find the no. plz
Answers
Answered by
1
Hi ,
We have to convert the given word problem into
algebraic equation.
Let the number = x
One fourth of the number = ( 1/4 ) × x = x / 4
Succeeding number of x = ( x + 1 )
One fifth of the above number = ( 1/5 ) × ( x + 1 )= ( x + 1 ) / 5
According to the problem ,
One fourhth of a number exceeds one fifth of its
succeeding number by 3.
x / 4 - ( x + 1 ) /5 = 3
LCM ( 4 , 5 ) = 4 × 5 = 20
[ 5x - 4 ( x + 1 ) ] / 20 = 3
5x - 4x - 4 = 3 × 20
x - 4 = 60
x = 60 + 4
x = 64
Therefore ,
Required number = x = 64
Verification:
x /4 - ( x + 1 ) /5 = 64 /4 - ( 64 + 1 ) / 5
= 16 - 13
= 3
I hope this helps you.
We have to convert the given word problem into
algebraic equation.
Let the number = x
One fourth of the number = ( 1/4 ) × x = x / 4
Succeeding number of x = ( x + 1 )
One fifth of the above number = ( 1/5 ) × ( x + 1 )= ( x + 1 ) / 5
According to the problem ,
One fourhth of a number exceeds one fifth of its
succeeding number by 3.
x / 4 - ( x + 1 ) /5 = 3
LCM ( 4 , 5 ) = 4 × 5 = 20
[ 5x - 4 ( x + 1 ) ] / 20 = 3
5x - 4x - 4 = 3 × 20
x - 4 = 60
x = 60 + 4
x = 64
Therefore ,
Required number = x = 64
Verification:
x /4 - ( x + 1 ) /5 = 64 /4 - ( 64 + 1 ) / 5
= 16 - 13
= 3
I hope this helps you.
kanupriya6:
plz explain it in easy way
Let x represent the digit, then
(1/4)x-(1/5)x=3
(5/20)x-(4/20)x=3
(1/20)x=3
x=60
the two-digit number is 60 and the difference between the digits, (6-0), is 6
(1/4)x-(1/5)x=3
(5/20)x-(4/20)x=3
(1/20)x=3
x=60
the two-digit number is 60 and the difference between the digits, (6-0), is 6
sorry i cant understand
byeeee
Answered by
0
Hey sup!
As per the question,
Let the number be x.
1/4 of number= 1/4*x = x/4
1/5 of succeeding number=1/5*(x+1)=(x+1) is/5.
So, x/4 - (x+1)/5 =3.
Taking LCM
=> (5x-4x-4)/20=3.
=>x-4=3*20.
=>x-4=60.
=>x=60+4=64.
So The number is 64.
Hope it helps.
As per the question,
Let the number be x.
1/4 of number= 1/4*x = x/4
1/5 of succeeding number=1/5*(x+1)=(x+1) is/5.
So, x/4 - (x+1)/5 =3.
Taking LCM
=> (5x-4x-4)/20=3.
=>x-4=3*20.
=>x-4=60.
=>x=60+4=64.
So The number is 64.
Hope it helps.
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