Math, asked by Sarim666, 7 months ago

plz solve...need some help​

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Answered by MysteriousAryan
11

Answer:

given - ps \: is \: median \:  \\ so \: as \: we \: know \: that \: sum \: of \:  \\ any \: two \: sides \: is \: greater \: than \: third \: side \: so \:  \\ pq \ + qs > ps -  -  -  -  - 1 \\ and \: pr + rs > ps -  -  -  - 2 \\  \\ add \: 1 \: and 2\: we \: get \: (Pq + pr) > 2ps \\ hence \: proved

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Answered by Anonymous
0

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Answer:

\begin{gathered}given - ps \: is \: median \: \\ so \: as \: we \: know \: that \: sum \: of \: \\ any \: two \: sides \: is \: greater \: than \: third \: side \: so \: \\ pq \ + qs > ps - - - - - 1 \\ and \: pr + rs > ps - - - - 2 \\ \\ add \: 1 \: and 2\: we \: get \: (Pq + pr) > 2ps \\ hence \: proved\end{gathered}

given−psismedian

soasweknowthatsumof

anytwosidesisgreaterthanthirdsideso

pq +qs>ps−−−−−1

andpr+rs>ps−−−−2

add1and2weget(Pq+pr)>2ps

henceproved

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