plz solve. Q.no. 23...
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if both roots are equal then the discriminant b2-4ac=0
(2mc)^2-4 (1+m^2)(c^2-a^2)=0
4m^2c^2-4 (c^2-a^2+m^2c^2-m^2a^2)=0
4m^2c^2-4c^2+4a^2-4m^2c^2+4m^2a^2=0
4a^2-4c^2+4m^2a^2=0
a^2-c^2+m^2a^2=0
c^2=a^2 (1+m^2)............hence proved
(2mc)^2-4 (1+m^2)(c^2-a^2)=0
4m^2c^2-4 (c^2-a^2+m^2c^2-m^2a^2)=0
4m^2c^2-4c^2+4a^2-4m^2c^2+4m^2a^2=0
4a^2-4c^2+4m^2a^2=0
a^2-c^2+m^2a^2=0
c^2=a^2 (1+m^2)............hence proved
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