plz solve Q1 Q2 Q3 plz
Answers
Answer:
1) avg speed = total distance/total time
total distance traveled =16+16=32
total time = 4+2 = 6sec
avg speed = 32/6 = 5.33 m/s.
2) avg speed = total distance/total time
we will find total distance as 2400‐2000=400km
total time = 8hr as given in the question
avg speed =400/8 = 50km/h.
3) after 10 sec the velocity will be 15m/s.
✪ Question (1) : ✪
An object travel 16 m in 4 second and then another 16 m in 2 second. What is the average speed of the object?
✪ AnsWer : ✪
- Distance (D₁) = 16 m
- Distance (D₂) = 16 m
- Time (T₁) = 4 s
- Time (T₂) = 2 s
- Average speed = ?
→Average speed = Total distance ÷ Total time
→Average speed = (D₁ + D₂) ÷ (T₁ + T₂)
→Average speed = (16 + 16) ÷ (4 + 2)
→Average speed = 32 ÷ 6
→Average speed = 5.34 s
✪ Question (2) : ✪
The odometer of a car reads 2000 km at the start of a trip and 2400 km at the end of the trip. If the trip take took 8 h, calculate the average speed of the car in km/h and m/s.
✪ AnsWer : ✪
- Initial reading [Distance] (D₁) = 2000 km
- Final reading [Distance] (D₂) = 2400 km
- Total Time (T) = 8 h
- Average speed = ?
↠Average speed = Total distance ÷ Total time
↠Average speed = (Final reading - initial reading) ÷ Total time
↠Average speed = (2400 - 2000) ÷ 8
↠Average speed = 400 ÷ 8
↠Average speed = 50 km/h
↠Average speed = 50 × (5/18)
↠Average speed = 250/18
↠Average speed = 13.9 m/s
✪ Question (3) : ✪
A body is moving with a velocity of 15 m/s. If the motion is uniform. What will be the velocity after 10 seconds.
✪ AnsWer : ✪
It is said that the body is moving with a uniform motion it means that acceleration must be 0 m/s².
- Initial velocity (u) = 15 m/s
- Acceleration (a) = 0 m/s²
- Time (t) = 10 s
- Final velocity (v) = ?
Now, apply first kinematical equation of motion :
↛v = u + at
↛v = 15 + (0) × 10
↛v = 15 m/s