Physics, asked by Zainab1210hassan, 1 year ago

plz solve qs no. 4 ASAP. ....will be glad..its an iit preparation based qs of class 11th ..waiting for your pleasure response

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Answered by mindSC
0

hey mate !!!

as per the condition, the particle moves 3m in x direction, 4m in the y direction and 5m in the z direction.

the the movement of the particle in the vectors term can be written as

3i + 4j + 5k

thus, the net displacement is

√(3^2 + 4^2 + 5^2)

= √(9+8+25)

=√(50)

=7.07

thus the net displacement is 7.07 units in the direction of vector

3i + 4j + 5k

hope you've found it informative !!!


Zainab1210hassan: tysm❤
mindSC: All the very best for your IIT exams ; )
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