plz solve que. 3,4,5 as soon as possible....
plz answer fast....
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5.... y=acos(logx)+bsin(logx) _(1)
dy/dx=a[-sin(logx)]×1/x+bcos(logx)×1/x
xdy/dx=-asin(logx)/x+bcos(logx)
xd²y/dx²+dy/dx =-acos(logx)-bsin(logx)/x
by cross multiple...
x²d²y/dx²+xdy/dx= -[acos(logx)+bsin(logx)]
x²d²y/dx²+xdy/dx=-y (from 1)
x²d²y/dx²+xdy/dx+y=0
hence proved
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