Question

plz solve ques 37 given​

Answer 1

Answer:

Step-by-step explanation:

Area of road parallel to length= 75*4 = 300 m^2

area of road parallel to breadth= 60*4 = 240 m^2

here, the overlapping region is considered twice.

it is a square of side 4m at the intersection of the two roads in the middle.

so, total area to be considered

= (300+240)-(4*4) = 524 m^2

cost of gravelling = rs. 50*524

= rs. 26200.