Question

plz solve ques no. 3

Answer 1

Answer:

No 3

Step-by-step explanation:

Let the tap with small diameter take X hr to fill the tank.

therefore ,the tap with larger diameter will take (x-10) hrs to fill the tank seperately

Now,

portion of the tank filled by the tap of smaller diameter in one hr = 1/x

Therefore. portion of the tank by the tap of smaller diameter in 93/8 hr i.e. 75 /8hr = 75/8x

Again portion of the tank filled by the tap of larger diameter in one hr= 1/x- 10

therefore, portion of the tank filled by the tap of larger diameter in 75/8hr = 75 /8(x-10)

it's given that both the tap together can fill the tank in 94/8=75/9hr

A/q

75/8x+75/8(x-10)=1

=75/8(1/X+1/x-10)=1

1/X+1/x-10=8/75

solve ti abit

=75(2x-10)= 8(x2_ 10x)

solve it more till it comes

4x2-115x +375=0

Now putit in the formula

Answer 2

Answer:

0 is answer dear friend