plz solve question 2.
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length = 6m
breadth = 4m
height = 12 m.
breadth = 4m
height = 12 m.
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6
Let the length and breadth of the room be l and b respectively.
Given that length of a room is 50% more than its breadth.
l = b + 50% of b
l = b + 50/100 * b
= b(1 + 50/100)
= b(150/100)
= b(3/2)
= 1.5b
Therefore the length = 1.5b ------- (1)
Given that cost of carpeting, the room at the rate of 38.50m^2 is 924 rupees.
We know that Area of the floor = l * b
l * b = 924/38.50
l * b = 24
1.5 b * b = 24
1.5b^2 = 24
b^2 = 24/1.5
b^2 = 16
b = 4. -------- (2)
Substitute b = 4 in (1) , we get
l = 1.5 * b
= 1.5 * 4
= 6. ---------------- (3)
Given that cost of carpeting, the walls at the rate of 5.50 per m^2 are 1320 rupees.
We know that Area of four walls = 2(l + b) * h
2(l + b) * h = 1320/5.50
2(6 + 4) * h = 240
2(10) * h = 240
20 * h = 240
h = 240/20
h = 12m. ----- (4)
Therefore from (2),(3),(4).
The dimensions of the room are:
Length = 6m.
Breadth = 4m.
Height = 12m.
Hope this helps!
Given that length of a room is 50% more than its breadth.
l = b + 50% of b
l = b + 50/100 * b
= b(1 + 50/100)
= b(150/100)
= b(3/2)
= 1.5b
Therefore the length = 1.5b ------- (1)
Given that cost of carpeting, the room at the rate of 38.50m^2 is 924 rupees.
We know that Area of the floor = l * b
l * b = 924/38.50
l * b = 24
1.5 b * b = 24
1.5b^2 = 24
b^2 = 24/1.5
b^2 = 16
b = 4. -------- (2)
Substitute b = 4 in (1) , we get
l = 1.5 * b
= 1.5 * 4
= 6. ---------------- (3)
Given that cost of carpeting, the walls at the rate of 5.50 per m^2 are 1320 rupees.
We know that Area of four walls = 2(l + b) * h
2(l + b) * h = 1320/5.50
2(6 + 4) * h = 240
2(10) * h = 240
20 * h = 240
h = 240/20
h = 12m. ----- (4)
Therefore from (2),(3),(4).
The dimensions of the room are:
Length = 6m.
Breadth = 4m.
Height = 12m.
Hope this helps!
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