Question

plz solve question 25 in step
steps answer will be marked as brainlist

Answer 1

Hi ,

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We know the algebraic identity,

If x + y + z = 0 then

x³ + y³ + z³ = 3xyz

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Now ,

a + b + c = 6 ----( 1 ) given

( 2 - a )³ + ( 2 - b )³ + ( 2 - c )³

Let x = 2 - a ,

y == 2 - b ,

z = 2 - c ;

x + y + z = 2 - a + 2 - b + 2 - c

= 6 - ( a + b + c )

= 6 - 6 [ from ( 1 ) ]

= 0

Therefore ,

( 2 - a )³ + ( 2 - b )³ + ( 2 - c )³ - 3(2-a)(2-b)(2-c)

= 3( 2 - a )(2-b ) ( 2 - c )-3(2-a)(2-b)(2-c)

= 0

I hope this helps you.

: )

Answer 2

hope helped you
please mark as brainlist