Physics, asked by alangeorge852, 1 year ago

plz solve question 3.18 with all steps ( no direct answer ) (need to be explained)

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Answered by 9552688731
1
Vpg = 30km/h = 30×5/18 = 8.3 m/s

Vbp = 150m/s

Vcg = 192km/h = 192×5/18 = 53.3m/s
______________

Vbp = Vbg - Vpg
Vbg = Vbp + Vpg
Vbg = 8.3+150 = 158.3 m/s
_____________

Vbc = Vbg - Vcg
Vbc = 158.3 - 53.3
Vbc = 105m/s
____________

so the bullet hits the thief's car at speed of 105m/s
_________

where ,
Vpg = velocity of police with respect to the ground
Vbp = velocity of bullet with respect to the police
Vcg = velocity of chor(thief) with respect to the ground
Vbg = velocity of bullet with respect to the ground
Vbc = velocity of bullet with respect to the chor(thief)
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