Question

Plz solve question 6 a) and 6 b)

Answer 1

6. b)

i) u = 18 km/h = 18000 m/h = $\frac{18000}{3600}$ m/s = 5 m/s

ii) v = u + at

0 = 18 + a(5)

5a = -18

a = -3.6 m/s²

retardation = 3.6 m/s²

iii) v = u + at = 18+(-3.6)2 = 18-7.2 = 10.8 m/s

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6. a)

density(ρ) = mass/volume

density of water = 1000 kg/m³

volume = mass/density of water = 1.5/1000 = 0.0015 m³

buoyancy force (F) = density(ρ) x g x volume displaced(V)

= 1000 x 9.8 x 0.0015

= 9.8 x 1.5

= 14.7 N