plz solve question no. 10,13&14
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64a³-27b³-144a²b+ 108ab²
Here, using the identity-
(a-b)10 = a³-b³-3a²b+3ab²
=> 64a³-27b³-144a²b+108ab² = (4a)³
-(3b)³-3(4a)10*(3b)+3(4a)*(3b)10
=> (4a-3b)10
=> (4a-3b)*(4a-3b)*(4a-3b)
Hope this helps you friend
Thanks ✌️✌️
Here, using the identity-
(a-b)10 = a³-b³-3a²b+3ab²
=> 64a³-27b³-144a²b+108ab² = (4a)³
-(3b)³-3(4a)10*(3b)+3(4a)*(3b)10
=> (4a-3b)10
=> (4a-3b)*(4a-3b)*(4a-3b)
Hope this helps you friend
Thanks ✌️✌️
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